Maria Menshikova
Appearance
(Redirected from Maria Alexandrovna Menshikov)
Maria Menshikova | |
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![]() Princess Maria; portrait by Johann Gottfried Tannauer | |
Born | Princess Maria Alexandrovna Menshikova 26 December 1711 Saint Petersburg |
Died | 26 December 1729 Berezovo |
Noble family | Menshikov |
Father | Alexander Danilovich Menshikov |
Mother | Daria Mikhailovna Arsenieva |
Princess Maria Alexandrovna Menshikova (26 December 1711 – 26 December 1729) was a daughter of Aleksandr Danilovich Menshikov, the favourite of Peter I of Russia.[1]
Life
[edit]She was the eldest daughter and first child of Prince Aleksandr Danilovich Menshikov and Daria Mikhailovna Arsenieva.[2]
Thanks to her father's influence in the Russian court, she was engaged to Grand Duke Peter of Russia, a grandson of Peter the Great.[3][1] Though they never married their engagement was announced and a dowry discussed. This proposal brought about the disgrace of her father who was subsequently exiled to Siberia.
After following her father into exile, she died of smallpox in Berezovo at age eighteen.
References
[edit]- ^ a b Bisha, Robin (January 1998). "Reconstructing the Voice of a Noblewoman of the Time of Peter the Great: Daria Mikhailovna Menshikova: An exercise in (pseudo) autobiographical writing". Rethinking History. 2 (1): 51–63. doi:10.1080/13642529809408761. ISSN 1364-2529.
- ^ Koeppe, Wolfram; Nudel, Marina (January 2000). "An Unsuspected Bust of Alexander Menshikov". Metropolitan Museum Journal. 35: 161–177. doi:10.2307/1513033. ISSN 0077-8958.
- ^ Bain, Robert Nisbet (1897). The Pupils of Peter the Great: A History of the Russian Court and Empire from 1697 to 1740. A. Constable & Company. pp. 128–134.