1874 Tennessee gubernatorial election
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 County results[1] Porter: 50–60% 60–70% 70–80% 80–90% >90% Maynard: 50–60% 60–70% 70–80% 80–90% >90% No data: | |||||||||||||||||
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| Elections in Tennessee |
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 Government |
The 1874 Tennessee gubernatorial election was held on November 3, 1874, to elect the next governor of Tennessee. Incumbent Democratic governor John C. Brown did not seek re-election. Democratic candidate James D. Porter defeated Republican congressman Horace Maynard with 65.20% of the vote.[2]
General election
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | James D. Porter | 105,061 | 65.20% | ||
| Republican | Horace Maynard | 55,847 | 34.66% | ||
| Greenback | B. F. Brooks | 222 | 0.14% | ||
| Total votes | 161,130 | 100.00% | |||
See also
[edit]- 1874 United States House of Representatives elections in Tennessee
- 1874 United States gubernatorial elections
References
[edit]- ^ This map is based on the data from ourcampaigns.com. The map data may not have the official totals.
- ^ Phillip Langsdon, Tennessee: A Political History (Franklin, Tenn.: Hillsboro Press, 2000), pp. 198-203.
- ^ Tennessee Blue Book (1890), 1874 Gubernatorial
- ^ "Our Campaigns - TN Governor Race - Nov 03, 1874 UNOFFICIAL RESULTS". www.ourcampaigns.com. Retrieved 2024-02-28.
Categories:
- Tennessee gubernatorial elections
- 1874 United States gubernatorial elections
- 1874 Tennessee elections
- 1874 in Tennessee
- 1870s in Tennessee
- 1870s Tennessee elections
- 1874 elections
- 1874 elections in North America
- 1874 elections in the United States
- November 1874 events in the United States
- United States gubernatorial elections in the 1870s
- Government of Tennessee