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1989 Singapore Open – Doubles

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Doubles
1989 Singapore Open
Final
ChampionsUnited States Rick Leach
United States Jim Pugh
Runners-upUnited States Paul Chamberlin
Kenya Paul Wekesa
Score6–3, 6–4
Events
Singles Doubles
Singapore Open · 1990 →

Rick Leach and Jim Pugh won in the final 6–3, 6–4 against Paul Chamberlin and Paul Wekesa.[1] [2]

Seeds

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Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top two seeded teams received a bye into the quarterfinals.

  1. United States Rick Leach / United States Jim Pugh (champions)
  2. Canada Grant Connell / Canada Glenn Michibata (semifinals)
  3. Australia Wally Masur / Australia Jason Stoltenberg (semifinals)
  4. United States Kelly Jones / United States Joey Rive (first round)

Draw

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Key

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First round Quarterfinals Semifinals Final
1 7 3 7
  6 6     6 6 6
  India M Ferreira
South Korea Young Min-kwon
0 1   1 2 7 6
3 7 6 6 3 6 6 4
  6 7 3 3 6 6  
  6 2 6   3 3  
  3 6 7 1 6 6  
  United States Weller Evans
United States P Fishbach
4 2     3 4  
  Sweden J Carlsson
Sweden Chris Lindoff
6 6     Sweden J Carlsson
Sweden C Lindoff
     
  3 6 7   w/o    
4 6 4 6   6 7 6
  Singapore Liu Sonny
Singapore Liu Wai-yaw
3 2   2 7 6 2
  Canada Art Hobbs
United States Andrew Turcinovich
6 6     Canada A Hobbs
United States A Turcinovich
4 2  
2 6 6  

References

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  1. ^ John Barrett, ed. (1990). The International Tennis Federation : World of Tennis 1990. London: Willow Books. p. 104, 146. ISBN 9780002183550.
  2. ^ "1989 Singapore – Doublesdraw". Association of Tennis Professionals (ATP).
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