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2017 Stockholm Open – Doubles

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Doubles
2017 Stockholm Open
Final
ChampionsAustria Oliver Marach
Croatia Mate Pavić
Runners-upPakistan Aisam-ul-Haq Qureshi
Netherlands Jean-Julien Rojer
Score3−6, 7−6(8−6), [10−4]
Events
Singles Doubles
← 2016 · Stockholm Open · 2018 →

Elias and Mikael Ymer were the defending champions, but lost in the first round to Marc López and Fernando Verdasco.

Oliver Marach and Mate Pavić won the title, defeating Aisam-ul-Haq Qureshi and Jean-Julien Rojer in the final, 3−6, 7−6(8−6), [10−4].[1]

Seeds

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Draw

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Key

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Draw

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First round Quarterfinals Semifinals Final
1 Austria O Marach
Croatia M Pavić
6 6
France J Eysseric
Croatia F Škugor
3 4 1 Austria O Marach
Croatia M Pavić
6 4 [10]
Israel J Erlich
Croatia N Mektić
5 77 [10] Israel J Erlich
Croatia N Mektić
3 6 [5]
Romania M Copil
Romania F Mergea
7 63 [8] 1 Austria O Marach
Croatia M Pavić
3 77 [10]
4 Austria A Peya
Brazil B Soares
77 6 4 Austria A Peya
Brazil B Soares
6 63 [8]
Spain D Marrero
Argentina L Mayer
65 3 4 Austria A Peya
Brazil B Soares
711 7
Netherlands R Haase
New Zealand M Venus
6 6 Netherlands R Haase
New Zealand M Venus
69 5
New Zealand M Daniell
Brazil M Demoliner
2 4 1 Austria O Marach
Croatia M Pavić
3 78 [10]
WC Sweden E Ymer
Sweden M Ymer
4 0 2 Pakistan A-u-H Qureshi
Netherlands J-J Rojer
6 66 [4]
Spain M López
Spain F Verdasco
6 6 Spain M López
Spain F Verdasco
2 67
India L Paes
India P Raja
6 63 [8] 3 United States J Sock
Serbia N Zimonjić
6 79
3 United States J Sock
Serbia N Zimonjić
3 77 [10] 3 United States J Sock
Serbia N Zimonjić
77 4 [6]
WC France J Chardy
Sweden R Lindstedt
3 1 2 Pakistan A-u-H Qureshi
Netherlands J-J Rojer
63 6 [10]
PR Italy S Bolelli
Italy F Fognini
6 6 PR Italy S Bolelli
Italy F Fognini
5 5
United States N Monroe
Australia J-P Smith
0 64 2 Pakistan A-u-H Qureshi
Netherlands J-J Rojer
7 7
2 Pakistan A-u-H Qureshi
Netherlands J-J Rojer
6 77

References

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  1. ^ "Marach/Pavic Bolster London Chances". APT World Tour. 22 October 2018. Retrieved 20 October 2018.
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