DeSoto Lake
Appearance
DeSoto Lake | |
---|---|
Location | Floyd County, Georgia |
Coordinates | 34°13′27″N 85°11′03″W / 34.2242°N 85.1843°W |
Type | reservoir |
Basin countries | United States |
Surface elevation | 189 m (620 ft) [1] |
![](http://upload.wikimedia.org/wikipedia/commons/thumb/e/e8/DeSoto_Lake%2C_Darlington_School%2C_Rome%2C_GA_Nov_2017.jpg/220px-DeSoto_Lake%2C_Darlington_School%2C_Rome%2C_GA_Nov_2017.jpg)
DeSoto Lake is a reservoir in Floyd County, in the U.S. state of Georgia.[1]
The lake was named for Hernando de Soto, a Spanish explorer.[2]
See also
[edit]References
[edit]- ^ a b U.S. Geological Survey Geographic Names Information System: DeSoto Lake
- ^ "Floyd County". Calhoun Times. September 1, 2004. p. 63. Retrieved 24 April 2015.