Talk:Reflected-wave switching

This article was nominated for deletion on 29 September 2017. The result of the discussion was keep.

The article says "its amplitude is added to that of the original pulse". I don't understand.

Is the following true: "The pulse duration is long enough that the original pulse is still present at the receiver when the echo of the pulse bounces back, hence they add in amplitude." Not terribly clearly written, but am I close?

Kentborg 14:51, 10 July 2007 (UTC)[reply]

I also found the above unclear and a diagram would surely help the explanation. It seems to assume that the microstrip continues past the receiver to a non-terminated end, and the continued length serves as a quarter-wave resonator. This means that the timing of the voltage overshoot depends on the position of the receiver on the microstrip. Does this also mean that the closer a receiver is to the transmitter, the longer the delay before it recognises a pulse? Cuddlyable3 (talk) 09:43, 10 September 2008 (UTC)[reply]