User:Raakin khan

Easy problems:

$\overbrace {1+2+\cdots +100} ^{5050}$

To, calculate the above summation problem, you can solve it using a lot of ways:

First, doing it completely manually:

1+2+3+4+5+6+...+100 = 5050

where, x = the last term = 100

There are a lot of ways to calculate the summations

Implementation of Raakin's summation formula.

$\overbrace {5+6+7+\cdots +44} ^{980}$

To calculate the problem above, Raakin's summation formula comes in handy.

which is,

${\biggl (}(x+y)(x-y)+\mathrm {N} (x+y){\Biggr )}\div 2\mathrm {N}$